shapely.disjoint

disjoint(a, b, **kwargs)

Return True if A and B do not share any point in space.

Disjoint implies that overlaps, touches, within, and intersects are False. Note missing (None) values are never disjoint.

Parameters:

a, bGeometry or array_like

Geometry or geometries to check.

**kwargs

See NumPy ufunc docs for other keyword arguments.

See also

intersects

disjoint(A, B) == ~intersects(A, B)

prepare

improve performance by preparing a (the first argument)

Examples

>>> import shapely
>>> from shapely import GeometryCollection, LineString, Point
>>> line = LineString([(0, 0), (1, 1)])
>>> shapely.disjoint(line, Point(0, 0))
False
>>> shapely.disjoint(line, Point(0, 1))
True
>>> shapely.disjoint(line, LineString([(0, 2), (2, 0)]))
False
>>> empty = GeometryCollection()
>>> shapely.disjoint(line, empty)
True
>>> shapely.disjoint(empty, empty)
True
>>> shapely.disjoint(empty, None)
False
>>> shapely.disjoint(None, None)
False